The usage of great deal of and a large amount of?

The usage of great deal of and a large amount of?

A great deal of uncountable nouns
A large amount of uncountable nouns amounts can be in the plural
The difference between a nember of, a great deal, a plenty of, a lot of
A lot of people are waiting for the bus.eg2 . A lot of money lies on the ground.2.a number o...
It is known that the numbers corresponding to two points a and B on the number axis are 6, - 8, and MnP is the number axis
Given two points a and B on the number axis, the corresponding numbers are 6, - 8. M.n.p are three moving points on the number axis. The speed of point m starting from point a is two consecutive units per second, the speed of point n starting from point B is three quilt of point m, and the speed of point P starting from the origin is one unit
(1) If point m moves to the right and point n moves to the left, how long is the distance between point m and point n 54 units?
(2) If point m.n.p moves to the right at the same time, how long does the distance from point P to point m.n equal?
(1) Let the distance between point m and point n be 54 Units after x seconds. According to the meaning of the problem, the equation can be listed as: 2x + 6x + 14 = 54. Solving the equation, we get x = 5. Answer: after 5 seconds, the distance between point m and point n is 54 units
(2) Let the distance from point P to point m and n be equal. (2t + 6) - t = (6t-8) - t or (2t + 6) - t = t - (6t-8), t + 6 = 5t-8 or T + 6 = 8-5t, so t = 7 / 2 or T = 1 / 3
A: after t = 7 / 2 or T = 1 / 3 seconds, the distance from point P to point m and N is equal
As shown in the figure, the numbers represented by a and B on the number axis are - 2 and 6 respectively
The point C on the number axis satisfies AC = BC, and the point D is on the extension line of the line AC. if ad = 3,2ac, then BD =?, and the number represented by the point D is an important process
c=（6-2）÷2=2；
ac=2-（-2）=4；
ad=6;
So d = 4 or - 8;
So BD = 2 or 14;
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Answer: BD = 2, D is 4
It is known that the numbers corresponding to two points a and B on the number axis are 6, - 8, and m, N and P are the three moving points on the number axis
It is known that the corresponding numbers of two points a and B on the number axis are 6, - 8 respectively. M, N and P are the three moving points on the number axis. The speed of point m starting from point a is 2 units per second, that of point n starting from point B is three times that of point m, and that of point P starting from the origin is 1 unit per second
(1) If points m, N and P move to the right at the same time, how long does the distance from point P to point m and N equal?
Let time be t (s)
Then M = 6 + 2T
N=-8+6t
P=t
When t
-The number of points corresponding to 2 and 2 divides the number axis into three segments. If at least three of any n different points on the number axis are in one of the segments, then what is the minimum value of N?
Drawer principle
The minimum value of n = 3 × (3-1) + 1 = 7
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Given that point a is small a on the number axis, B is small B, and the absolute value of small a + 2 + the square of small B-5 = 0.1, find the length 2 of the line segment, set point P as X, the absolute value of PA + the absolute value of Pb
When value = 10, find the value of X
3, m and N start from O and B respectively, and the velocities of V1 and V2 move in the negative direction on the number axis at the same time. M is on the line AO and N is on Bo. When m moves to point a or point n moves to point O, another point stops moving. P is the midpoint of line an. When Mn moves to any moment, the absolute value of PM is constant. Only one of the following statements is true. The value of 1, V1 / V2 remains unchanged. The value of 2, V1 + V2 remains unchanged
According to the question meaning: 1. A + 2 + (B-5) ^ 2 = 0, so a = - 2, B = 5, ab = 5 + 2 = 72. PA + / / Pb = / / x + 2 + / / X-5 = 10, the equation is solved to get x = - 1.5, or x = 6.53. Let time be t, then M = - v1t, n = 5-v2t, P = (5-v2t + 2) / 2-2 = (3-v2t) / 2 │ PM = (3-v2t) / 2 + v1t = / / 3 / 2 + (2
As shown in the figure, there is a point P on the line AB, and the points m and N are the midpoint of the line PA and Pb respectively, ab = 14
(3) As shown in the figure, if point C is the midpoint of line AB and point P is on the extension line of line AB, the following conclusions can be drawn:
① The values of pa-pb / PC and PA + Pb / PC are the same. Please choose a correct conclusion and find its value
solution
The value of (PA + Pb) / PC remains unchanged
∵ C is the midpoint of ab
∴AC＝BC＝AB/2
∴PA＝AB+BP＝2AC+BP
∴PA+PB＝2AC+PB+PB＝2（AC+PB）
∵PC＝AP-AC＝2AC+PB-AC＝AC+PB
∴（PA+PB）/PC＝2（AC+PB）/（AC+PB）＝2
(PA + Pb) / PC = 2, unchanged
The first question is not complete, is it for Mn?
∵ m is the midpoint of PA
∴AM＝PM＝AP/2
∵ n is the midpoint of Pb
∴BN＝PN＝BP/2
∴MN＝PM+PN＝AP/2+BP/2＝（AP+BP）/2＝AB/2
∵AB＝14
∴MN＝14/2＝7
The value of (PA + Pb) / PC does not change in solving the first problem
∵ C is the midpoint of ab
∴AC＝BC＝AB/2
∴PA＝AB+BP＝2AC+BP
∴PA+PB＝2AC+PB+PB＝2（AC+PB）
∵PC＝AP-AC＝2AC+PB-AC＝AC+PB
∴（PA+PB）/PC＝2（AC+PB）/（AC+PB）＝2
The value of (PA + Pb) / PC = 2, the first topic does not expand
The value of (PA + Pb) / PC does not change in solving the first problem
∵ C is the midpoint of ab
∴AC＝BC＝AB/2
∴PA＝AB+BP＝2AC+BP
∴PA+PB＝2AC+PB+PB＝2（AC+PB）
∵PC＝AP-AC＝2AC+PB-AC＝AC+PB
∴（PA+PB）/PC＝2（AC+PB）/（AC+PB）＝2
The value of (PA + Pb) / PC = 2, unchanged. The first question is incomplete. Is it Mn?
∵ m is the midpoint of PA
∴AM＝PM＝AP/2
∵ n is the midpoint of Pb
∴BN＝PN＝BP/2
∴MN＝PM+PN＝AP/2+BP/2＝（AP+BP）/2＝AB/2
∵AB＝14 ∴MN＝14/2＝7
Solution 2 because AP = 8, ab = 14, P is a point on AB, so Pb = 6. Because points m and N are the midpoint of line PA and Pb, so MP = 4, nd = 3, so Mn = 7
(2) point P is on the Ba extension line
∵ point m is the midpoint of AP
∴PM=MA=1/2AP
∵ point n is the midpoint of BP
∴PN=NB=1/2PB
∴MN=NP－MP=1/2PB－1/2AP=1/2(PB－AP)=1/2AB=7
② Point P is between a and B
∵ point m is the midpoint of AP
∴PM=MA=1/2AP
∵ point n is the midpoint of BP
∴PM=NB=1/2PB MN=MP+NP=1/2AP+1/2PB=1/2AB=1/2×14=7
③ Point P is on the extension line ab
∵ point m is the midpoint of AP
∴AM=MP=1/2AP
∵ point n is the midpoint of BP
∴PN=NB=1/2PB
∴MN=MP－NP=1/2AP－1/2BP=1/2(AP－BP)=1/2×14=7
The value of solution 3PA + Pb) / PC remains unchanged
∵ C is the midpoint of ab
∴AC＝BC＝AB/2
∴PA＝AB+BP＝2AC+BP
∴PA+PB＝2AC+PB+PB＝2（AC+PB）
∵PC＝AP-AC＝2AC+PB-AC＝AC+PB
∴（PA+PB）/PC＝2（AC+PB）/（AC+PB）＝2
The value of (PA + Pb) / PC = 2, unchanged and folded
(1) If point P is on line AB and AP = 8, find the length of line Mn
(2) If point P moves on line AB, the length of segment Mn has nothing to do with the position of point P on line ab
(3) As shown in the figure, if point C is the midpoint of line AB and point P is on the extension line of line AB, the following conclusions can be drawn: (1) the value of pa-pb / PC remains unchanged. (2) The value of PA + Pb / PC remains unchanged, please choose a correct conclusion and find its value
(1) If point P is on line AB and AP = 8, find the length of line Mn
(2) If point P moves on line AB, the length of segment Mn has nothing to do with the position of point P on line ab
(3) As shown in the figure, if point C is the midpoint of line AB and point P is on the extension line of line AB, the following conclusions can be drawn: (1) the value of pa-pb / PC remains unchanged. (2) The value of PA + Pb / PC remains unchanged. Please choose a correct conclusion and calculate its value
The value of (PA + Pb) / PC remains unchanged
∵ C is the midpoint of ab
∴AC＝BC＝AB/2
∴PA＝AB+BP＝2AC+BP
∴PA+PB＝2AC+PB+PB＝2（AC+PB）
∵PC＝AP-AC＝2AC+PB-AC＝AC+PB
∴（PA+PB）/PC＝2（AC+PB）/（AC+PB）＝2
(PA + Pb) / PC = 2, unchanged
The second question
1 because AP = 8 AB = 14 P is a point on AB, Pb = 6
Because points m and N are the midpoint of line PA and Pb respectively
So MP = 4 nd = 3
So Mn = 7
(2) point P is on the extension line of Ba
∵ point m is the midpoint of AP
∴PM=MA=1/2AP
∵ point n is the midpoint of BP
∴PN=NB=1/2PB
The expansion of Mn = np-mp = 1 / 2pb-1 / 2AP = 1 / 2 (pb-ap) = 1
1 because AP = 8 AB = 14 P is a point on AB, Pb = 6
Because points m and N are the midpoint of line PA and Pb respectively
So MP = 4 nd = 3
So Mn = 7
(2) point P is on the extension line of Ba
∵ point m is the midpoint of AP
∴PM=MA=1/2AP
∵ point n is the midpoint of BP
∴PN=NB=1/2PB
∴MN=NP－MP=1/2PB－1/2AP=1/2(PB－AP)=1/2AB=7
② Point P is between a and B ∵ point m is the midpoint of AP
∴PM=MA=1/2AP
∵ point n is the midpoint of BP
∴PM=NB=1/2PB MN=MP+NP=1/2AP+1/2PB=1/2AB=1/2×14=7
③ Point P is on the extension line of AB, and point m is the midpoint of AP
∴AM=MP=1/2AP
∵ point n is the midpoint of BP
∴PN=NB=1/2PB
Ψ Mn = mp-np = 1 / 2ap-1 / 2bp = 1 / 2 (ap-bp) = 1 / 2 × 14 = 7
To solve the first problem, the value of (PA + Pb) / PC remains unchanged ∵ C is the midpoint of ab ∵ AC = BC = AB / 2 ∵ PA = AB + BP = 2Ac + BP ∵ PA + Pb = 2Ac + Pb + Pb = 2 (AC + Pb) ∵ PC = ap-ac = 2Ac + Pb-Ac = AC + Pb ∵ (PA + Pb) / PC = 2 (AC + Pb) / (AC + Pb) = 2 ∵ the value of (PA + Pb) / PC = 2, the first problem is not complete, is it to find Mn? ∵ m is the midpoint of PA ∵ am = PM = AP / 2 ∵ n is p... expansion
To solve the first problem, the value of (PA + Pb) / PC remains unchanged ∵ C is the midpoint of ab ∵ AC = BC = AB / 2 ∵ PA = AB + BP = 2Ac + BP ∵ PA + Pb = 2Ac + Pb + Pb = 2 (AC + Pb) ∵ PC = ap-ac = 2Ac + Pb-Ac = AC + Pb ∵ (PA + Pb) / PC = 2 (AC + Pb) / (AC + Pb) = 2 ∵ the value of (PA + Pb) / PC = 2, the first problem is not complete, is it to find Mn? ∵ m is the midpoint of PA ∵ am = PM = AP / 2 ∵ n is the midpoint of Pb ∵ BN = PN = BP / 2 ∵ Mn = PM + PN = AP / 2 + BP / 2 = (AP + BP) / 2 = AB / 2 ∵ AB = 14 ∵ Mn = 14 / 2 = 7
Solution 2: because AP = 8, ab = 14, P is a point on AB, Pb = 6. Because points m and N are the midpoint of line PA and Pb, MP = 4 and nd = 3, Mn = 7 (2) point P is on Ba extension line ∵ point m is the midpoint of AP ∵ PM = ma = 1 / 2AP ∵ point n is the midpoint of BP ∵ PN = NB = 1 / 2PB ∵ Mn = np-mp = 1 / 2pb-1 / 2AP = 1 / 2 (pb-ap) = 1 / 2Ab = 7; point P is between a and B ∵ point m is the midpoint of AP ∵ PM = ma = 1 / 2AP ∵ point n is the midpoint of BP ∵ PM = NB = 1 / 2PB Mn = MP + NP = 1 / 2AP + 1 / 2PB = 1 / 2Ab = 1 / 2 × 14 = 7 ∵ point P is on the extension line of ab ∵ point m is the midpoint of AP ∵ am = MP = 1 / 2AP ∵ point n is the midpoint of BP ∵ PN = NB = 1 / 2PB ∵ Mn = mp-np = 1 / 2ap-1 / 2bp = 1 / 2 (ap-bp) = 1 / 2 × 14 = 7
The value of 3PA + Pb) / PC remains unchanged ∵ C is the midpoint of ab ∵ AC = BC = AB / 2 ∵ PA = AB + BP = 2Ac + BP ∵ PA + Pb = 2Ac + Pb + Pb = 2 (AC + Pb) ∵ PC = ap-ac = 2Ac + Pb-Ac = AC + Pb ∵ (PA + Pb) / PC = 2 (AC + Pb) / (AC + Pb) = 2