Are a number of and the number of plural nouns? Can we add uncountable nouns?

Are a number of and the number of plural nouns? Can we add uncountable nouns?

may not
A number of can only modify the plural form of countable nouns
The number of can only add the plural form of countable nouns, because it is interpreted as: the number of, uncountable nouns have no specific number
A number of. The predicate is usually plural
The number of. When used with a plural noun as subject, the head word is number and the predicate verb is singular.
Is the Olympics the subject and the predicate singular or plural?
But the Olympic Games is plural. For example, the Olympic Games are held every four years
Plural is a combined noun, there is no singular form
singular
Olympics Games is also singular.
Often said
the Olympics is more than medels.
the Olympics
It means the Olympic Games. It's singular
There are also many nouns ending with s, but it is a singular concept, and the predicate verb should be singular
It should be in the plural... My English teacher said....
Not necessarily. If it means that athletes or organizers should have PL, others should be singular
If for all real numbers x, y has f (x + y) = f (x) + F (y)
Find f (0) and prove that f (x) is an odd function
Let x = - y, then f (0) = f (x) + F (- x) = 0. Why is f (- x) = - f (x) ‖ an odd function rather than f (- x) = f (x) ‖ an even function?
F (x + y) = f (x) + F (y) let x = y = 0, f (0 + 0) = f (0) + F (0) f (0) = 0, any x ∈ R, f (x + (- x)) = f (x) + F (- x), that is, 0 = f (0) = f (x) + F (- x) ∧ f (- x) = - f (x). F (x) is an odd function. A special case of this function is f (x) = 2xf (x + y) = 2 (x + y) = 2x + 2Y = f (x) + F (y)
Let y = - x, then f (x + y) = f (x) + F (y)
f(0)=f(x)+f(-x) ....1
f(x+0)=f(x)+f(0)
f(x)=f(x)+f(0)
∴f(0)=0
Substituting 1,
Ψ f (- x) = - f (x), that is, f (x) is an odd function
Let x = y = 0, because for all real numbers x, y has f (x + y) = f (x) + F (y);
So there is: F (0 + 0) = f (0) + F (0), that is, f (0) = 2F (0),
So f (0) = 0
Let x = x, y = - x, because for all real numbers x, y has f (x + y) = f (x) + F (y);
Then f (x-x) = f (x) + F (- x), that is, f (0) = f (x) + F (- x) = 0 {because f (0) = 0}
So f (x) = - f (- x)
So the function is odd
f(0)=f(x)+f(-x)=0?
It's not mentioned in the title
How to distinguish plural nouns in English,
Why does ideas emotions have plural while information has no plural? Is emotion countable
Emotion = happy, sad, angry, etc are defined as the found group
Too much information, news, email, phone, TV, radio, etc
Like sugar and candy. Can sugar be digital? Can candy
There are two kinds of complex numbers. One is the number of direct congeners, which can be counted. For example, idea, you can say one idea has two ideas. The other is the category, such as emotion. You can say one emotion and two emotions.
There are two kinds of words without plural number. One is that they can't count one by one, such as sugar. The other is the general name of nouns, such as information, such as furniture. But sometimes these nouns can also be used as the second kind of plural number, that is, they can be counted on the number, such as fruits and vegetables
Mathematical odd even function
1. The functions f (x) and G (x) are all odd functions in the interval [- A, a], and G (x) is not equal to 0, then the following functions are: 1. F (x) + G (x) 2. F (x) - G (x) 3. F (x) * g (x) 4. In F (x) divided by G (x), the odd function is_________
2. It is known that the quadratic function f (x) is an even function and passes through points (3,6), and an analytic expression of it is obtained
! @ remember the odd and even sum and difference operations. The same even gets even. The same odd gets odd. The difference is neither odd nor even (note that y = 0 is both odd and even)
If we divide the remainder by the same, we will be even; if we divide by the different, we will be odd
See for yourself
Let y = AX2 + B, then you can bring in (3,6) and get a, (first assume that B can be any value)
1. Answer: 1, 2
2. Answer: let the analytic expression of the function be y = ax ^ 2 + BX + C
Because the function passes the point (3,6) and the function is even
So 6 = 9A + 3B + C
6=9a-3b+c
So B = 0
c=6-9a
That is y = ax ^ 2-9a + 6
When a = 1, C = - 3
Here y = ax ^ 2-3
1. Functions f (x) and G (x) are all odd functions in the interval [- A, a], and G (x) is not equal to 0, then the following functions:
1.f(x)+g(x)
2.f(x)-g(x)
3.f(x)*g(x)
4. In F (x) of G (x), 1,2 are odd functions
2. It is known that the quadratic function f (x) is an even function and passes through points (3,6), and an analytic expression of it is obtained. It's a process
y=ax²+c
6 = 9A + c... expansion
1. Functions f (x) and G (x) are all odd functions in the interval [- A, a], and G (x) is not equal to 0, then the following functions:
1.f(x)+g(x)
2.f(x)-g(x)
3.f(x)*g(x)
4. In F (x) of G (x), 1,2 are odd functions
2. It is known that the quadratic function f (x) is an even function and passes through points (3,6), and an analytic expression of it is obtained. It's a process
y=ax²+c
6=9a+c
Y = ax & sup2; + (6-9A)
Words ending with F can be changed from F to ves in plural, or s can be added directly
Handkerchief
For example, lazy people.
parity function
1-x if x = 0
Odd function or even function
Even function
An image is symmetric about the y-axis, and the center of symmetry is a (0,1) point pair function
F (x) = 1 + | x |, so it's even.
For any X in the domain of definition of function f (x), if f (x) = f (- x), it is an even function
For any X in the domain of F (x), if f (x) = - f (x) is an odd function
1-x if x = 0
According to the above definition, the function is neither odd nor even.
Even function. Just draw the image
What are the plurals of nouns ending in f or Fe
Quick memory: the thief's wife killed a wolf with a leaf knife
Key words: thief, soft, leaf, knife, wolf, life
I hope I can help you remember
When the following nouns ending in f or Fe become plural, add - s directly. The nouns of roof heads plus ves are: half → haves knife → knives leaf → leaves wolf → woods
Mathematics: on the parity of functions
If f (x) is an odd function defined on R and X is greater than 0, f (x) = 2x & sup2; - x + 3, then what is the analytic expression of F (x) when x is less than 0?
How to solve this kind of problem? I'm a sophomore in high school. I still make every mistake in this kind of problem. Please list the detailed steps. It's better to explain. Thank you
If f (x) is an odd function defined on R and X is greater than 0, f (x) = 2x & sup2; - x + 3, then what is the analytic expression of F (x) when x is less than 0?
Let x0, so f (- x) = 2 (- x) ^ 2 - (- x) + 3 = 2x ^ 2 + X + 3
F (- x) = - f (x)
So, when x0, f (x) = 2x ^ 2-x + 3
When x = 0, f (x) = 0
How to pronounce the plural of th with S
Th voiced consonant / ð /, plus s, pronounce / Z/
When pronouncing the consonant / θ /, add s, pronounce / s/