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∵a=3,b=5∴c=2.設|PF1|=t1,|PF2|=t2,則由橢圓的定義可得:t1+t2=6①在△F1PF2中∠F1PF2=60°,∴t12+t22-2t1t2•cos60°=16②,由①2-②得t1t2=16,∴S=12|PF1|•|PF2|sin60°=12×16×32=43.
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