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z=(1+xy)^y=e^[(ln(1+xy))*y]取對數:lnz=y*ln(1+xy)求全微分:dz/z=(1/(1+xy))y*ydx+ln(1+xy)dy+(xy/(1+xy))dy=(1/(1+xy))y*ydx+[ln(1+xy)+(xy/(1+xy))]dy所以:dz/dy=[(1+xy)^y]*[ln(1+xy)+(xy/(1+xy))]…
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