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因為f(2)=f(a) 把x=2,x=a代入函數.所以-4+4a+a^2=-a^2+2a^2+a^2,解得a=2 代入原式得:f(x)=-x^2+4x+4,變形後得到,f(x)=-(x-2)^2+8,該函數的頂點就是x=2,y=8,即是該函數的最大值.
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