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令f(x,y,z)=e^z-z+xy; 則 偏f/偏x=y; 偏f/偏y=x; 偏f/偏z=e^z-1. 在點(2,1,0)處,x=2,y=1,z=0,則此處 偏f/偏x=1;偏f/偏y=2;偏f/偏z=0. 切面方程為:1×(x-2)+2×(y-1)+0×(z-0)=0 即x+2y=4.
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