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是不是 y= x^2 -3* |x-1| -1 (|x-1|指絕對值) 那就是求 x^2 -3* |x-1| -1 =0的解的個數 x^2-1=3* |x-1| (x-1)(x+1)=3* |x-1| x-1=0 or x+1=正負3 x=1 or x=-4 or x=2 所以有3個交點!
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