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∵點G為△ABC重心,DE經過點G,DE‖BC,∴ADAB=23,∵△ADE∽△ABC,∴S△ADES△ABC=(23)2,∵S△ABC=18,∴S△ADE=8,同理可得 ;S△CEF=2,∴四邊形BDEF的面積等於18-8-2=8.
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