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根據題意,對x分3種情况討論:①當x≥12時,原不等式可化為x+3+2x-1≥7,解得x≥53,②當-3≤x<12時,原不等式可化為x+3+1-2x≥7,解得解得x≤-3,所以x=-3,③當x<-3 ;時,原不等式可化為-x-3+ 1-2x≥7,解得x<-3,綜上,原不等式的解集為(-∞,-3]∪[53,+∞).
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