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等邊△ABC的邊長為a,∵點O為△ABC的內心,∴OE⊥AB,AE=BE=a2,∠EAO=30°,∴OE=AE•tan∠EAO=36a,則正方形的邊長是2OE•cos45°=2×22OE=2×22×36a=66a.則正方形的面積是:16a2.
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