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由一次函數的圖像可知,圖像過(1,0),(0,-2)兩點,設一次函數的解析式為:y=kx+b(k≠0),把(1,0),(0,-2)兩點代入,得k+b=0b=−2,解得k=2b=−2.故所求一次函數的解析式為:y =2x-2.
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