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當x<-1時有1>1,∴無解當-1≤x≤0時,有(1-x²;)²;+1>1,∴x≠±1,∴-1<x<0.當0≤x≤0時,有(1-x²;)²;+1>(2x)²;+1,∴0≤x<(根2)-1當x>1時,有1>(2x)²;+1,∴無解綜…
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