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設x<0,則-x>0f(-x)=1而函數y=f(x)是R上奇函數則f(-x)=-f(x)=1即f(x)=-1∴當x<0時,f(x)=-1根據函數y=f(x)是R上奇函數則f(-0)=-f(0)=f(0)即f(0)=0綜上所述函數y=f(x)的運算式是f(x)=1,…
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