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(3x-2)^2=(x+4)^2 (3x-2)^2-(x+4)^2=0 [(3x-2)+(x+4)][(3x-2)-(x+4)]=0 (4x+2)(2x-6)=0 4x+2=0,或2x-6=0 x=-½;,或x=3
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