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設直線方程y-2=k(x+1)即kx-y+2+k=0與圓x²;+y²;=5相切,即與原點的距離是√5.利用點到直線的距離公式,√5=|2+k|/√(k²;+1),整理得4k²;-4k+1=0,解得k=1/2.所以直線方程是1/2x-y+5/2=0.其實,為什麼…
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