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a²;-2ab+b²;-c²;=(a-b)²;-c²;=(a-b+c)(a-b-c)其中a-b+c=a+c-b>0----------因為三角形的兩邊和大於第三邊a-b-c=a-(b+c)<0-----因為三角形的兩邊和大於第三邊所以可知道上面的式是負的啊…
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