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根據題意,圓心在直線y=x上 設圓心為(a,a) 那麼 √(a-8)²;+(a-1)²;=a a²;-16a+64+a²;-2a+1=a²; a²;-18a+65=0 (a-13)(a-5)=0 a=13或5 圓的方程:(x-13)²;+(y-13)²;=169或(x-5)²;+(y-5)²;=25
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