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f(x)=lnx=ln(2+(x-2))=ln{2[1+(x-2)/2]}=ln2+ln[1+(x-2)/2]; 然後把ln(1+x)的展開式中的x用(x-2)/2替換即可,這個書上可以找到的. ln(1+x)的級數展開收斂域為(-1,1],囙此新的級數為(x-2)/2∈(-1,1]; x∈(0,4]
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