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由已知,A^(n-k)αk=αn≠0,A^(n-k+1)αk=Aαn=0下證α1,α2,…,αn線性無關設k1α1+k2α2+…+knαn=0用A^(n-1)左乘上式的兩邊,得k1αn=0由於αn≠0,所以k1=0所以k2α2+…+knαn=0同理,用A^(n-2)左乘上…
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