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證明:因為(√2+√3)(√2-√3)=-1,(√2+√3)+(√2-√3)=2√2故√2+√3是方程x^2-2√2x-1=0的根x^2-2√2x-1=0,乘以x^2+2√2x-1得:(x^2-1)^2-(2√2x)^2=0,即:x^4-10x^2+1=0取f(x)=x^4-10x^2+1,則f(x)為有理數域上…
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