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把(X+1)+(1+X)^2+.+(1+X)^10按等比數列求和得 [(1+x)-(1+x)^10]/(-x). 囙此,只須求出分子中,(1+x)^10中,x^4的係數即可. 由二項式通項公式得C(10)4=210, 所以展開式中X^3的係數210.
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