求lim [sin（x^2-1）]/（x-1）x趨向於1的極限.

求lim [sin（x^2-1）]/（x-1）x趨向於1的極限.

lim（x→1）[sin（x^2-1）]/（x-1）= lim（x→1）{[sin（x^2-1）/（x^2-1）]×（x+1）}
=lim（x→1）[sin（x^2-1）/（x^2-1）]×lim（x→1）（x+1）
=1×（1+1）=2.

Elden Ring Premiere

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