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∫[0,a]ln(x+√(a^2+x^2)dx =xln(x+√(a^2+x^2))|[0,a] -∫[0,a]x[1+x/√(a^2+x^2)]dx/[x+√(a^2+x^2)] =aln(a+√2a)-∫[0,a]xdx/√[a^2+x^2] =aln(a+√2a)-√(a^2+x^2)|[0,a] =aln(a+√2a)-√2a+a
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