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證:設偶函數為f(x),奇函數為g(x) 則之和:h(x)=f(x)+g(x) 因為f(x)=f(-x),g(x)=-g(-x) 所以h(-x)=f(-x)+g(-x)=f(x)-g(x) 所以h(x)≠h(-x),h(x)+h(-x)=2f(x)≠0 所以奇函數與偶函數之和為非奇非偶函數
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