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因為5、10、15、20、25、…、450與其它偶數之積的個位至少有一個0450÷5=90個,450÷25=18,90+18=108個,即連續自然數乘積1×2×3×…×450的尾部恰有108個連續的0,而125可以貢獻3個0所以1×2×3×…×n中,n的最大值是444.答:自然數n的最大值是444.
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