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當x0所以f(-x)=(-x)^2-2(-x)+1=x^2+2x+1 -f(x)=x^2+2x+1 f(x)=-x^2-2x-1 當x>0時,已知f(x)=x^2-2x+1 所以f(x)=x^2-2x+1(x>0) =0(x=0) =-x^2-2x-1(x
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