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函數y=|lg(x+1)|=lg(x+1),x≥0−lg(x+1),−1<x<0,函數的定義域為x>-1,根據複合函數的單調性,所以函數y=|lg(x+1)|的單調增區間是[0,+∞),故答案為:[0,+∞).
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