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y=-x^2-4x+4=-(x^2+4x+4)+8=-(x+2)^2+8. 1、當-t+2=4,所給定義域在對稱軸左側,此時,最大值在x=-t+2處達到,即: f(x)max=f(2-t)=-(4-t)^2+8; 2、當-t
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