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根據“其中一個質因數是兩位數,它的數位之和是11,並要求這個質數盡可能大”推得這個質數是83因有4個不同的質因數,這個自然數的形式為A^M*B^N*C^P*D^Q根據約數個數公式32 =(M + 1)×(N + 1)×(P + 1)×(Q + 1),乘…
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