It is known that the length of a rectangle is twice the side length of a square, the width is 2 cm more than the side length of the square, and the area of the rectangle is 96 square cm larger than the area of the square. Find the side length of the square and the length and width of the rectangle

It is known that the length of a rectangle is twice the side length of a square, the width is 2 cm more than the side length of the square, and the area of the rectangle is 96 square cm larger than the area of the square. Find the side length of the square and the length and width of the rectangle

Let the side length of a square be a cm, the length of a rectangle be 2A cm, and the width be (a + 2) cm
From the meaning of the title, we can get the conclusion
2a(a+2)-a^2=96
2a^2+4a-a^2=96
a^2+4a-96=0
(a+12)(a-8)=0
A1 = - 12
a2=8
The length of square is 8cm; the length of rectangle is 16cm and the width is 10cm