Let x1, X2 be the two real roots of the equation x2 + PX + q = 0, and X1 + 1, X2 + 1 be the two real roots of the equation x2 + QX + P = 0 about X, then P= ，q= ．

∵ x1, X2 are the two real roots of the equation x2 + PX + q = 0, ∵ X1 + x2 = - P, x1x2 = q and ∵ X1 + 1, X2 + 1 are the two real roots of the equation x2 + QX + P = 0 about X, ∵ X1 + 1) + (x2 + 1) = - Q, (x1 + 1) (x2 + 1) = P, ∵ - P + 2 = - Q, Q-P + 1 = P, that is, P-Q = 2, 2p-q = 1, the solution is p = - 1, q = - 3