Given the line L: y = 3x + 3, find the equation of (1) line L with respect to the symmetric line at point m (3,2)

Given the line L: y = 3x + 3, find the equation of (1) line L with respect to the symmetric line at point m (3,2)

Let any point a (x, y) on a straight line be B (x ', y') with respect to point m (3,2), then M is the midpoint of line AB (the definition of symmetry), then x '+ x = 6 (3 * 2) y' + y = 4 (2 * 2) y = 3x + 3 is substituted into the second formula to get y '+ 3x + 3 = 4. The third formula is transformed into x = 6-x' and substituted into the third formula to get y '+ 3 (6-x') + 3 = 4 to get y '= 3x'