Find the range of function y = sin (2x + π / 3), X ∈ (- π / 6, π)
∵x∈(-π/6,π);
∴2x+π/3∈(0,2π+π/3);
Then the maximum value of function y is 1 and the minimum value is - 1;
Then y ∈ [- 1,1]
∵x∈(-π/6,π);
∴2x+π/3∈(0,2π+π/3);
Then the maximum value of function y is 1 and the minimum value is - 1;
Then y ∈ [- 1,1]