Let ∑ be a sphere x ^ 2 + y ^ 2 + Z ^ 2 = 4, then the curved area is divided into ∮ (x ^ 2 + y ^ 2 + Z ^ 2) ds=

Let ∑ be a sphere x ^ 2 + y ^ 2 + Z ^ 2 = 4, then the curved area is divided into ∮ (x ^ 2 + y ^ 2 + Z ^ 2) ds=

Area element DS = 2 / (4-x ^ 2-y ^ 2) ^ 1 / 2dxdy
∫∫(x^2+y^2+z^2)dS=x^2+y^2+z^2)dS=∫∫4.2/(4-x^2-y^2)^1/2dxdy
Polar coordinate transformation: ∫ ∫ (x ^ 2 + y ^ 2 + Z ^ 2) ds = 4 π R ^ 4 = 64 π
Handle the details by yourself