Given: X / 2 = Y / 3 = Z / 4, find (x2 + y2-z2-2xy) / (x2-y2 + z2-2xz) divided by (x2-y2-z2 + 2yz) / (x2 + y2-z2 + 2XY)

Given: X / 2 = Y / 3 = Z / 4, find (x2 + y2-z2-2xy) / (x2-y2 + z2-2xz) divided by (x2-y2-z2 + 2yz) / (x2 + y2-z2 + 2XY)

Let X / 2 = Y / 3 = Z / 4 = K
Then x = 2K, y = 3k, z = 4K, you can calculate the result by substituting the formula you want, because the formula is quadratic, and finally K can be eliminated