The linear equation passing through point (1, - 1, - 2) and perpendicular to plane 2x-2y + 3Z = 0

The linear equation passing through point (1, - 1, - 2) and perpendicular to plane 2x-2y + 3Z = 0

The direction of the normal vector of the plane is (2, - 2,3)
Passing through point (1, - 1, - 2) and straight line direction can determine straight line
Let a point on a straight line (x, y, z)
Then (x-1) / 2 = (y + 1) / (- 2) = (Z + 2) / 3
I don't remember the specific standard form of spatial straight line. If you need to change it into standard form, you can do it according to the textbook