Given xy = 35, find the value of x2 − XY + 2y2x2 + 2XY − Y2

Given xy = 35, find the value of x2 − XY + 2y2x2 + 2XY − Y2

∵ xy = 35, ∵ YX = 53, the denominator of x2 − XY + 2y2x2 + 2XY − Y2 is divided by XY at the same time to get XY − 1 + 2yxxy + 2 − YX, ∵ original formula = XY − 1 + 2yxxy + 2 − YX = 35 − 1 + 10335 + 2 − 53 = 44151415 = 4414 = 227