As shown in the figure, the image of the first-order function y equal to minus 2x plus B and the image of the second-order function y equal to minus xsquare plus 3x plus C pass through the origin (1) If the line y = KX + m and the line y = negative 2x + B are parallel to the Y axis and intersect at point a and pass through the vertex P of the parabola to find the expression of the line y = KX + m, and (3) find the area of the triangle apo

As shown in the figure, the image of the first-order function y equal to minus 2x plus B and the image of the second-order function y equal to minus xsquare plus 3x plus C pass through the origin (1) If the line y = KX + m and the line y = negative 2x + B are parallel to the Y axis and intersect at point a and pass through the vertex P of the parabola to find the expression of the line y = KX + m, and (3) find the area of the triangle apo

Take (0,0) into y = - 2x + B to get: B = 0
Take (0,0) into y = x & # 178; + 3x + C to get: C = 0
So the analytic expressions of the functions are y = - 2x and y = x & # 178; + 3x
2)y=x²+3x=(x+3/2)²-9/4
So p (- 3 / 2, - 9 / 4)
So the analytical formula of the straight line is: y = - 2x-21 / 4
3) If P (- 3 / 2, - 9 / 4) is brought into y = - 2x + m, M = - 21 / 4
Let x = 0 in y = - 2x-21 / 4, then y = - 21 / 4
So a (0, - 21 / 4)
Area of triangle apo = 1 / 2 * 21 / 4 * 3 / 2 = 63 / 16