In the plane rectangular coordinate system, the line y = KX + B intersects with the negative half axis of X axis at point a, and the positive half axis of Y axis at point B. the circle P passes through points a and B (the center P of the circle is on the negative half axis of X axis). It is known that ab = 10, AP = 25 / 4 1) The analytic formula of the straight line y = KX + B 2) Is there a point Q on the circle P such that the quadrilateral with apbq as its vertex is a diamond? If it exists, request the coordinates of point Q

In the plane rectangular coordinate system, the line y = KX + B intersects with the negative half axis of X axis at point a, and the positive half axis of Y axis at point B. the circle P passes through points a and B (the center P of the circle is on the negative half axis of X axis). It is known that ab = 10, AP = 25 / 4 1) The analytic formula of the straight line y = KX + B 2) Is there a point Q on the circle P such that the quadrilateral with apbq as its vertex is a diamond? If it exists, request the coordinates of point Q

1)
A(-b/k,0),B(0,b)
BP=AP=25/4
sinP=|b|/BP=4|b|/25
sin(P/2)=(AB/2)/BP=4/5
cos(P/2)=3/5
sinP=2*sin(P/2)*cos(P/2)=24/25
4|b|/25=24/25
|b|=6
OA=√(AB^2-|b|^2)=8>AP
Point a is on the negative half axis of x-axis
-b/k=-8
When B = 6, k = 3 / 4
The analytic formula of straight line y = 3x / 4 + 6
When B = - 6, k = - 3 / 4
The analytic formula of straight line y = - 3x / 4-6
2) It doesn't exist
AB and PQ are equally divided vertically
PQ = 2 * √ [AP ^ 2 - (AB / 2) ^ 2] = 6 / 5 is not equal to the radius of circle P, AP = 25 / 4, so q is not on circle P