It is known that the center of circle C is on the straight line 2x-y-3 = 0, and the standard equation of circle C can be obtained through points a (5,2), B (3,2)

It is known that the center of circle C is on the straight line 2x-y-3 = 0, and the standard equation of circle C can be obtained through points a (5,2), B (3,2)

It is known that the center of circle C is on the straight line 2x-y-3 = 0
Let C (x ', 2x' - 3) be the center of the circle
The distance between C and a, B is the radius R
r^2=(x'-5)^2+(2x'-3-2)^2=(x'-3)^2+(2x'-3-2)^2
That is, (x '- 5) ^ 2 = (x' - 3) ^ 2
The solution is x '= 4
Then the center of circle C (4,5)
Radius R ^ 2 = (4-5) ^ 2 + (5-2) ^ 2 = 10
So the standard equation of circle C (x-4) ^ 2 + (Y-5) ^ 2 = 10
I hope I can help you. I wish you progress in your study_ ∩)O