It is known that the right quasilinear of two hyperbolas is x = 4, the right focus is f (10.0), and the eccentricity is e = 2?

It is known that the right quasilinear of two hyperbolas is x = 4, the right focus is f (10.0), and the eccentricity is e = 2?

Let the center of hyperbola be: (D, 0)
The right guide line is x = 4: A ^ 2 / C = 4-D
Right focus f (10,0), C = 10-d
The centrifugal ratio is e = 2, C / a = 2
Solving equations
a^2/c=4-d
c=10-d
c/a=2
The results are as follows
a=4,c=8,d=2
b^2=c^2-a^2=48
Hyperbolic equation: (X-2) ^ 2 / 16-y ^ 2 / 48 = 1

Elden Ring Premiere

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