As shown in the figure, we know that the image of the first-order function intersects the image of the positive proportion function at point m, intersects the x-axis at point n (- 6,0), and we also know the coordinates of point m (- 4,m). If the area of △ mon is 15, we can find the analytic expressions of the positive proportion function and the first-order function

As shown in the figure, we know that the image of the first-order function intersects the image of the positive proportion function at point m, intersects the x-axis at point n (- 6,0), and we also know the coordinates of point m (- 4,m). If the area of △ mon is 15, we can find the analytic expressions of the positive proportion function and the first-order function

Let MC = m (m ＞ 0) pass through the point m to get 12on × M = 15 from the area of △ mon 15, on = 6, that is, 12 × 6 × M = 15, M = 5, and m (- 4,5). Let the analytic expression of positive proportion function y = K1X (K1 ≠ 0), substitute x = - 4, y = 5, and get K1 = − 54, y = − 54x. Let the analytic expression of primary function y = k2x +