Given that 1 divided by x plus 1 divided by Y equals 3, find 3x + XY + 3Y divided by x-xy + y

Given that 1 divided by x plus 1 divided by Y equals 3, find 3x + XY + 3Y divided by x-xy + y

1/x+1/y=3
(3x + XY + 3Y) / (x-xy + y) divided by XY
=(3/y+1+3/x)/(1/y-1+1/x)
=(9+1)/(3-1)
=5