The last two digits are 42, the sum of numbers is 42, and what is the smallest of the natural numbers divisible by 42? It's a process

The last two digits are 42, the sum of numbers is 42, and what is the smallest of the natural numbers divisible by 42? It's a process

The last two digits are 42, and the sum of numbers is 42. From small to large, they are: 999942, 1899942, 1989942, 1998942, 1999842, 2799942, 2979942
The first six items can not be divided by 42, and the seventh item is 2979942 △ 42 = 70951;
Answer: the smallest is 2979942