Given that the natural numbers x and y satisfy the equation x & sup2; - Y & sup2; = 13, find the values of X and y On factorization X & sup2; - Y & sup2 is the square of x minus the square of Y

Given that the natural numbers x and y satisfy the equation x & sup2; - Y & sup2; = 13, find the values of X and y On factorization X & sup2; - Y & sup2 is the square of x minus the square of Y

x²-y²=13
(x+y)(x-y)=13=13*1
x+y=13
x-y=1
x=7
y=6
or
x+y=1
x-y=13
X = 7, y = - 6 (not rounding off)