If x ^ 2 + ax-9 = (x + m) (x + n) m, n is a positive integer, then the value of natural number a is? A.0, - 8.8b. Plus or minus 8 c.0, - 8 d.0,8 d.0 If x ^ 2 + ax-9 = (x + m) (x + n) n is an integer, then there is the value of natural number a? A. 0, - 8.8 B. plus or minus 8 C. - 8 d.0,8

If x ^ 2 + ax-9 = (x + m) (x + n) m, n is a positive integer, then the value of natural number a is? A.0, - 8.8b. Plus or minus 8 c.0, - 8 d.0,8 d.0 If x ^ 2 + ax-9 = (x + m) (x + n) n is an integer, then there is the value of natural number a? A. 0, - 8.8 B. plus or minus 8 C. - 8 d.0,8

Your question is wrong. Since m and N are positive integers, then "- 9" is wrong. According to the options, I guess it should be X & # 178; + ax-9 = (x + m) (x-n) ∵ X & # 178; + ax-9 = (x + m) (x-n), m and N are positive integers. According to Weida's theorem, - a = N-M - 9 = - nm, that is, a = M-N 9 = Mn ∵ 9 = 1 × 9 9 = 3 × 3 ∵ M-N = 9-1 =