Find the sum of the last two digits of M = 1! + 2! + 3! +. + 2003! + 2004

Find the sum of the last two digits of M = 1! + 2! + 3! +. + 2003! + 2004

four
Don't consider the sum of 10! To 2004! Because their last two digits must be 00
1!+2!+3!+4!+5!+6!+7!+8!+9!
=1+2+6+24+120+720+5040+40320+362880
=409113
So the sum of the last two digits is 4