lim n-> inf Xn=n^2/(n+1)-[n^2/(n+1)] Such as the title Find the value of LIM n - > inf xn Xn = n^2/(n+1)-[n^2/(n+1)] Where the meaning of [] is rounding Inf means infinity

lim n-> inf Xn=n^2/(n+1)-[n^2/(n+1)] Such as the title Find the value of LIM n - > inf xn Xn = n^2/(n+1)-[n^2/(n+1)] Where the meaning of [] is rounding Inf means infinity

n^2/(n+1)=(n^2-1+1)/(n+1)=n-1+1/(n+1)
So [n ^ 2 / (n + 1)] = n-1
Xn=1/(n+1)
limXn=0