In sequence an, A1 = 1 / 4, when n > = 2, there is (3N ^ 2-2n-1) an = a1 + A2 + a3 +. + a (n-1) (1) . find an (2) . find the first n terms and Sn

In sequence an, A1 = 1 / 4, when n > = 2, there is (3N ^ 2-2n-1) an = a1 + A2 + a3 +. + a (n-1) (1) . find an (2) . find the first n terms and Sn

(3N ^ 2-2n-1) an = a1 + A2 + a3 +. + a (n-1) [3 (n-1) ^ 2-2 (n-1) - 1] an-1 = a1 + A2 + a3 +. + a (n-2) subtraction (3N ^ 2-2n-1) an - [3 (n-1) ^ 2-2 (n-1) - 1] a (n-1) = a (n-1) (3N ^ 2-2n-1) an = [3N ^ 2-6n + 3-2n + 2-1 + 1] a (n-1) (3N ^ 2-2n-1) an = [3N ^ 2-8n + 5] a (n-1) (3N