Given the partial sum of series Sn = 2n / N + 1, find U1, U2, UN

Given the partial sum of series Sn = 2n / N + 1, find U1, U2, UN

u1=S1=1
u1+u2=S2=4/3 u2=4/3-1=1/3
Un=Sn-S(n-1)=2n/(n+1)-2(n-1)/(n)=2/[n(n+1)]